一个一个结果对比了，发现结果都对啊，但是没有通过。。。
其实很简单，就是在原来魔兽世界一的基础上多加了一个武器的功能，然而自己还是搞了一个小时，两周前写的程序都忘完了，发现自己当时写的程序注释不够详细，所以才会导致程序中的变量好多都忘了。吸取教训，要注释的详细一点，你的遗忘速度真的很快！！！
原题地址http://cxsjsxmooc.openjudge.cn/2019t3sprintw5/003/
#include <iostream>
#include<vector>
#include<string>
#include<map>
#include<iomanip>
#include<fstream>
using namespace std;
typedef map<string, int> strintmap;
//每个战士的生命值
static strintmap strength;
//武器名
static vector<string> weapon;
//map<string, int> strength;
//14:30-16:30
//21：25
class Warcraft {
public:
//司令部名
string name_;
//战士名
vector<string> nameSeq_;
//生命值
int lifeNum_;
//正在构造的第几个
//第几个战士索引
int ith;
//第几个战士的数量索引数组
int countIth[5];
//总战士人数
int countSum;
//是否已经输出构造完的消息了，构造结束标志
bool hasCout;
Warcraft(string name, const vector<string> &nameSeq, int lifeNum) {
name_ = name;
nameSeq_ = nameSeq;
lifeNum_ = lifeNum;
ith = 0;
countSum = 0;
hasCout = false;
for (int i = 0; i < 5; i++)
countIth[i] = 0;
}
bool born(int time)
{
for (int i = 0; i < 5; i++)
{
//bug1 差点写出bug。。。卧槽
if (hasCout)
{
return false;
}
//bug2 不能在这里用i++，因为这里+过后就会影响后面的i
else if (strength[nameSeq_[ith]] > lifeNum_)
{
ith = (ith + 1) % 5;
continue;
}
else
{
countIth[ith]++;
countSum++;
//bug 5 忘写这一句话了
//bug 6 一开始把这句话写在ith=(ith+1)%5下面了。。。。
lifeNum_ -= strength[nameSeq_[ith]];
cout << setw(3) << setfill('0') << time << " " << name_ << " " << nameSeq_[ith] << " " << countSum << " born with strength " << strength[nameSeq_[ith]] << "," << countIth[ith] << " " << nameSeq_[ith] << " in " << name_ << " headquarter" << endl;
//bug 4 ith=(ith++)%5为什么不行？？？
if (nameSeq_[ith] == "dragon")
{
cout << "it has a " <<weapon[countSum%3]<< ", and it's morale is " << fixed <<setprecision(2) << ((float)lifeNum_)/strength[nameSeq_[ith]] << endl;
}
else if (nameSeq_[ith] == "ninja")
{
cout << "It has a "<<weapon[countSum%3]<<" and a "<<weapon[(countSum+1)%3]<< endl;
}
else if (nameSeq_[ith] == "iceman")
{
cout << "It has a "<< weapon[countSum % 3] << endl;
}
else if (nameSeq_[ith] == "lion")
{
cout << "It's loyalty is "<< lifeNum_ << endl;
}
ith = (ith + 1) % 5;
return true;
}
}
cout << setw(3) << setfill('0') << time << " " << name_ << " headquarter stops making warriors" << endl;
hasCout = true;
return false;
}
};
int main()
{
//静态变量初始化
weapon.push_back("sword");
weapon.push_back("bomb");
weapon.push_back("arrow");
vector<string> redName;
vector<string> blueName;
redName.push_back("iceman");
redName.push_back("lion");
redName.push_back("wolf");
redName.push_back("ninja");
redName.push_back("dragon");
blueName.push_back("lion");
blueName.push_back("dragon");
blueName.push_back("ninja");
blueName.push_back("iceman");
blueName.push_back("wolf");
char a[5][10] = { "dragon", "ninja", "iceman", "lion", "wolf" };
int n, M;
cin >> n;
for (int ii = 0; ii < n; ii++)
{
cin >> M;
cout << "Case:" << ii + 1 << endl;
for (int i = 0; i < 5; i++)
{
int temp;
cin >> temp;
//bug 3 a[i]写成了a[0]。。。
//strength[a[i]] = temp;
strength[a[i]] = temp;
}
Warcraft wRed("red", redName, M);
Warcraft wBlue("blue", blueName, M);
int time = 0;
//bug 7 这个是在上面while退出时，这一时刻输出了headquarter stops making warriors，但是time++没有执行，所以需要在while之外加上这句
//bug 8 如果两者是同时退出的话，上面的&&只要第一个wRed不满足后，就不会再执行后面的wBlue了，所以此时不能time++
//一定要确定谁先执行完，如果使用下面这种同时判断wRed和wBlue，则不能确定是谁先执行完了
//while (wRed.born(time) && wBlue.born(time))
//{
// time++;
//}
while (wRed.born(time))
{
wBlue.born(time);
time++;
}
while (wBlue.born(time))
{
time++;
}
/下面这种情况会遇到的问题是：
//当输入为
//5000
//200 400 6 70 20 时,
//wRed和wBlue同时到达了最终要输出stops making warriors。但是程序在判断了wRed.born(time)为false后就不会执行后面的了。
//此时后面的语句不应该time++。 这样就和bug 7那里冲突了，不知道什么时候该time++，因为不知道两个谁先结束，所以最后的解决办法是上面的while (wRed.born(time)) { }
//while (wRed.born(time) && wBlue.born(time))
//{
// time++;
//}
bug 7 这个是在上面while退出时，这一时刻输出了headquarter stops making warriors，但是time++没有执行，所以需要在while之外加上这句
//time++;
//while (wBlue.born(time))
//{
// time++;
//}
//while (wRed.born(time))
//{
// time++;
//}
//return 0;
}
//n = 1, M = 20;
//for (int i = 0; i < 5; i++)
//{
// strength[a[i]] = i+3;
//}
return 0;
}
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原文链接：北大MOOC第五周003:魔兽世界之二：装备，转载请注明来源！